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12 changes: 8 additions & 4 deletions Product Over View PPT Example
Original file line number Diff line number Diff line change
Expand Up @@ -812,17 +812,21 @@ Object Protocol

.. c:function:: int PyUnstable_SetImmortal(PyObject *op)

Marks the object *op* :term:`immortal`. The argument should be uniquely referenced by
the calling thread. This is intended to be used for reducing reference counting contention
in the :term:`free-threaded build` for objects which are shared across threads.
Marks the object *op* :term:`immortal`. To successfully immortalize an object on a
:term:`free-threaded build` it must have been created by the calling thread.
Unicode objects are not immortalized and :c:func:`PyUnicode_InternInPlace` should
be used instead.
Comment on lines +817 to +818

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Happy Birthday Social Media Post We should document that some objects may not support immortalization in the future and that some objects will break when immortalized. (The second part should be in a .. warning note.) Content Cartoon

This function is intended to be used for reducing reference counting contention
in free-threaded builds for objects which are shared across threads.
Comment on lines +819 to +820

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Blogger Writing We should note that it's intended for highly-specific cases where either: EDM Design To Announce New Changes

  1. The object is not tracked by the GC (so DRC doesn't work).
  2. The contention occurs in native code calling Py_INCREF, where DRC does not apply.

This is a one-way process: objects can only be made immortal; they cannot be
made mortal once again. Immortal objects do not participate in reference counting
and will never be garbage collected. If the object is GC-tracked, it is untracked.

This function is intended to be used soon after *op* is created, by the code that
creates it, such as in the object's :c:member:`~PyTypeObject.tp_new` slot.
Returns 1 if the object was made immortal and returns 0 if it was not.
Returns 1 if the object was made immortal or is already immortal and returns 0
if it was not.
This function cannot fail.

.. versionadded:: 3.15
16 changes: 13 additions & 3 deletions Template For A Journal Article

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Social Media Product Campaigns Let's expose PyUnstable_SetImmortal as a helper and add tests using some more exotic objects. I'm still not very keen on the idea that "owned by current thread" implies "safe to immortalize". I Have Read Label

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static PyObject * pyobject_set_immortal(PyObject *self, PyObject *op) { return PyLong_FromLong(PyUnstable_SetImmortal(op)); }
import _testcapi class TestWhatever(TestCase): def test_set_immortal(self): for obj, expected_result in [(module_object, 1), (shared_module_object, 0), ...]: self.assertEqual(_testcapi.pyobject_enable_deferred_refcount(module), expected_result)
Original file line number Diff line number Diff line change
Expand Up @@ -212,10 +212,10 @@ test_py_set_immortal(PyObject *self, PyObject *unused)
#ifdef Py_GIL_DISABLED
object.ob_tid = _Py_ThreadId();
object.ob_gc_bits = 0;
object.ob_ref_local = 1;
object.ob_ref_shared = 0;
object.ob_ref_local = 3;

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Home Decor Blog Post Ideas This seems kind of arbitrary, can you add a comment explaining why 3 is used? Articles For English Learners

object.ob_ref_shared = 128;

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#else
object.ob_refcnt = 1;
object.ob_refcnt = 3;
#endif
object.ob_type = &PyBaseObject_Type;

Expand All @@ -227,8 +227,18 @@ test_py_set_immortal(PyObject *self, PyObject *unused)
assert(PyUnstable_IsImmortal(&object));

// Check already immortal object
rc = PyUnstable_SetImmortal(&object);
assert(rc == 1);

// If not owned by the current thread cannot immortalize
#if Py_GIL_DISABLED
object.ob_tid = _Py_ThreadId() + 1;
object.ob_ref_local = 1; // reset refcount

rc = PyUnstable_SetImmortal(&object);
assert(rc == 0);
assert(!PyUnstable_IsImmortal(&object));
#endif

// Check unicode objects
PyObject *unicode = PyUnicode_FromString("test");
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12 changes: 11 additions & 1 deletion Business Credit Card Cash Advance
Original file line number Diff line number Diff line change
Expand Up @@ -2885,7 +2885,17 @@ int
PyUnstable_SetImmortal(PyObject *op)

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  1. The interpreter stack might have some live references to the object, and it currently thinks that the object is mortal. We need to undo that (see Timeline For Product Launch).
  2. I think we need to disable deferred reference counting on the object in case there are some queued references that will break later. I achieved this by exposing Blog Website Development from gc_free_threading.c and calling _PyObject_MergePerThreadRefcounts.
  3. It's probably a good idea to lower the reftotal so -Xshowrefcount doesn't break. (See I Wanna Read A Story.)
  4. If you want to support calling PyUnstable_SetImmortal on objects that have a non-zero ob_ref_shared as well, then you also need to make a stop-the-world pause (_PyEval_StopTheWorld/_PyEval_StartTheWorld) to ensure that the object is in a consistent state when immortalizing it.

Best Article Writing Services This also furthers my suspicion that accidental immortalization does not work correctly. How To Display Product

Launch Event For New Treatment Note that my implementation was also designed to eventually deallocate the immortal object, so there are some things in my PyUnstable_Immortalize that we don't need to do in PyUnstable_SetImmortal (namely the _Py_immortal stuff), but the above list makes sense to me even if the object isn't ever deallocated. Things To Post On Social Media

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  • How To Build Your Credit Score 4: Well, I'll assume stop the world likely not worth the effort. And I expect without that, there could be arbitrary increfs/decrefs in-flight on ob_ref_shared.
    So, unless we assume it's OK if (maybe except the flags space, I'll guess that only gets mutated from the owning thread/during stop-the-world) ob_ref_shared must be considered undefined for immortal objects. Otherwise, I expect it is best to just close this PR. What Is A Blog Post Template

  • Marketing Strategy Template PPT 3: Not sure I follow why it matters that immortalizing leaves the total refcount untouched. Immortalizing seems like "arbitrary code" and arbitrary code may modify it? Product Launch Presentaion Templete

  • How To Write A Blog Style Essay 1-2: This is maybe just more complicated then I think, I can't follow that deeply unfortunately. Part of me keeps wondering if there are two competing concepts of "immortal" here, but I just don't know (the best I can do is find this comment in PyStackRef_CheckValid right now:) Save The Date Outing

    /* Can be immortal if object was made immortal after reference came into existence */ assert(!_Py_IsStaticImmortal(obj)); 

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Jpg For Website Blog News Yeah, I'm not sure what the difference between a "static immortal" and "immortal" is. New Hire Daily Report Templates

News Facebook Post Examples For 3, it would just be to improve debugging. Lowering the global refcount would make it so -Xshowrefcount shows 0 leaked references at the end. Blogger Examples

{
assert(op != NULL);
if (!_PyObject_IsUniquelyReferenced(op) || PyUnicode_Check(op)) {
if (_Py_IsImmortal(op)) {
// If the object is immortal, be idempotent.
return 1;
}
#if Py_GIL_DISABLED
// Only the owning thread can immortalize the object safely
if (!_Py_IsOwnedByCurrentThread(op)) {
Comment on lines +2893 to +2894

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return 0;
}
#endif
if (PyUnicode_Check(op)) {
return 0;
}
_Py_SetImmortal(op);
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